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A solution prepared by dissolving 1.2 g of urea and 1.8 g of glucose in 100 ml of water at $27^{0} C$ . The osmotic pressure of solution.

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8.2 atm

9.42 atm

7.389 atm

73.89

answer is B.

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Detailed Solution

$\begin{array}{l} π = C R T \\ = \frac{n}{V} R T \\ = \frac{(0.02 + 0.01)}{0.1} \times 0.0821 \times 300 \\ = 7.389 a t m \end{array}$

$\frac{1.2}{60} = 0.02 m o l e u r e a \frac{1.80}{180} = 0.01 m o l e g l u \cos e$

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