A sonar device on a submarine sends out a signal and receives an echo 5sec later. Calculate the speed of sound in water if the distance of the object from the submarine is 3625m:

The technological tool known as SONAR, or sound navigation and ranging, operates on the idea of sound reflection. When a submarine or other object reflects an ultrasonic wave sent by Sonar towards the ocean or sea floor, the reflected wave returns. The total distance covered by the sonar waves will be determined, and the velocity of the sonar wave will be determined by the relationship between distance, speed, and time.

Sonar is a tool that uses sound waves to locate objects underwater. Sonars are devices that send ultrasonic waves into the water beneath a ship and listen for echoes that come back from the seabed. Any object that is struck by these ultrasonic waves will produce a returning echo, which the sonar display will pick up on. The transducer is the apparatus that produces the ultrasonic waves.
Sonar, also known as sound navigation and range, is a technique used to acoustically locate and measure the distance and direction of underwater objects. Sonar equipment detects and analyses sound waves that are emitted by or reflected from an underwater object to determine what information is contained within.
Sonar operates on the basis of sound reflection. When a submarine or other object reflects an ultrasonic wave sent by Sonar towar the ocean or sea floor, the reflected wave returns. The time it took the ultrasonic wave to arrive at the sonar is then recorded. By combining the time and wave speed, we may use this information to determine where submarines or other undersea objects are.

It is explained to us that a sonar system on a submarine transmits a signal and gets an echo. The item is 3625 meters. The object's away from the submarine, so we need to figure out the water's sound speed.
The object's separation from the submarine is 3625 meters.
Duration of the echo, t=5sec
the distance the sonar waves covered overall during signal transmission and reception,

$D=2d=2\times 3625m$
$D=7250 \mathrm{m}$
Speed of the sound in water,
$v=\frac{D}{t}$
Put,
$D=7250 \mathrm{m}$
$t=5\sec$
$v=\frac{7250}{5}=1450{ \mathrm{ms}}^{-1}$
The speed of sound in water is $1450{ \mathrm{ms}}^{-1}$

Hence, the correct answe is option A.