A sound source S is vibrating at the open mouth of a quinker’s tube as shown in the figure. At another mouth, analyser A is situated which analyses the amplitude and intensity of vibration. The tube SBA is stationary whereas the tube SCA is movable. The minimum intensity at A for any position of C is 81 units. This intensity constantly increases to 1600 units at a distance of 1.65cm from this position. If the frequency of sound emitted by the source is X Hz, then the value of X/1000 will be …..
$V = 330 m / s$

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Detailed Solution

$\begin{array}{l} Δ = \frac{λ}{2} = 2 X 1.65 X 10^{- 2} m \\ n = \frac{V}{λ} = \frac{330}{4 X 1.65 X 10^{- 2}} = 5000 H z \end{array}$

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