A sound wave has frequency 500 Hz and velocity 360 m,/sec. What is the distance between two particles having phase difference of 60^o ?

$$\begin{gathered} \lambda =\frac{V}{n}=\frac{360}{500}=0\cdot 72m \\ Phase diff of 6^0 will correspond to a path difference \\ O.721 6 = 0 12m = 12\text{'}0cm \\ \text{'}A phase difference of 360\text{'}is caused due to a path differerce of \\ \text{ difference of }\lambda \text{ ) } \\ So, the distance between two particles having phase \\ difference of 60" = 12.ocm. \end{gathered}$$