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A source is emitting sound of a single frequency, a reflecting surface is advancing towards the source. The percentage of change of frequency of the note received by an observer near the source is 22.2%. Then the velocity of reflecting surface is

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15 m/s

30 m/s

45 m/s

60 m/s

answer is B.

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Detailed Solution

The apparent frequency received by the reflecting surface is n'

$n' = \frac{330 + v}{330}$

The apparent frequency received by the observer near the source is n''.

$n'' = \frac{330}{330 - v} n' = \frac{330 + v}{330 - v} n$

$\frac{Δn}{n} \times 100 = \frac{2 v}{330 - v} \times 100$

on solving $v ≃ 30 m / s$

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