A source of frequency ‘X’ gives 5 beats/s when sounded with a source of frequency 200 Hz. The second harmonic of source gives 10 beats/s when sounded with a source of frequency 420 Hz. The value of ‘x’ is

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

195 Hz

200 Hz

205 Hz

210 Hz

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

The value of x is either (200+5)or (200-5) Hz
The second harmonic of ‘x’ is either
(420+10)or (420–10) Hz ; from this data, it is
clear that, if x = 205 Hz
The second harmonic is '2x' i.e, 410 Hz

Watch 3-min video & get full concept clarity

tricks from toppers of Infinity Learn

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

🔥 Start Your JEE/NEET Prep at Just ₹1999 / month - Limited Offer! Check Now!

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET