A source of frequency ‘X’ gives 5 beats/s when sounded with a source of frequency 200 Hz. The second harmonic of source gives 10 beats/s when sounded with a source of frequency 420 Hz. The value of ‘x’ is

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195 Hz

200 Hz

205 Hz

210 Hz

answer is C.

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Detailed Solution

The value of x is either (200+5)or (200-5) Hz
The second harmonic of ‘x’ is either
(420+10)or (420–10) Hz ; from this data, it is
clear that, if x = 205 Hz
The second harmonic is '2x' i.e, 410 Hz

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