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A source of sound and listener are approaching each other with a speed of 40 m/s. The apparent frequency of note produced by the source is 400 cps. Then, its true frequency (in cps) is (velocity of sound in air = 360 m/s)

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420

360

400

320

answer is D.

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Detailed Solution

$n' = n (\frac{v + v_{O}}{v - v_{S}}) n \Rightarrow 400 = n (\frac{360 + 40}{360 - 40}) \Rightarrow n = 320 cps$

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