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Q.

A source of sound gives 5 beats per second when sounded with another source of frequency 100 second-1. The second harmonic of the source, together with a source of frequency 205 second-1 gives 5 beats per second. What is the frequency of the source ?

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a

95 second -1

b

100 second -1

c

205 second -1

d

105 second -1

answer is C.

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Detailed Solution

Frequency of source
=100±5=105 Hz  or  95Hz   As the second harmonic gives 5 beats/secoud with sound of frequency 205 Hz, the second harmonic should  be ( 205 ±5) Hz . So frequency of second harmonic is given by  2f = 200 Hz or 210 Hz . So f = 100 Hz or 105 Hz.    Frequency of the source = 1O5Hz

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