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Q.

A source of sound is moving with a velocity of 50 $m s^{- 1}$ towards the stationary observer. The observer
measures the frequency of sound as 500 Hz. The apparent freqeucny of sound as heard by the observer when the source is moving away from him with the speed is (speed of sound at room temperature 350 m/s)

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a

400Hz

b

666 Hz

c

375 Hz

d

177.5 Hz

answer is C.

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Detailed Solution

$V_{s} = 50 m / s, V_{0} = 0, V = 350 m / s, v^{1} = 500 H z$

Source is moving towards stationary observer $v_{1} = (\frac{V}{V - V_{s}})$
Source is moving away from the stationary observer
$\begin{array}{l} v^{11} = (\frac{V}{V + V_{s}}) v \\ \frac{v^{11}}{v^{1}} = (\frac{V - V_{s}}{V + V_{s}}) \\ v^{11} = (\frac{V - V_{s}}{V + V_{s}}) v^{1} = (\frac{350 - 50}{350 + 50}) 500 = 375 H z \end{array}$

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