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A source of sound is travelling towards a stationary observer. The frequency of sound heard by the observer is 25% more that of the actual frequency. If the speed of sound is v. Then that of the source is

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v /5

v /4

v /3

v /2

answer is A.

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Detailed Solution

n¹ = n + 25%n
$n^{1} = (\frac{V}{V - V_{s}}) n = \frac{5}{4} n \Rightarrow n^{1} = (\frac{V}{v - V_{s}}) n = \frac{5}{4} n$

$\Rightarrow 5 V - 5 V_{s} = 4 V = V_{s} = \frac{V}{5}$

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