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Q.

A source producing sound of frequency 170 Hz is approaching a stationary observer with a velocity 17 ms–1. The apparent change in the wavelength of sound heard by the observer is (speed of sound in air = 340 ms–1)

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a

0.5m

b

0.2m 

c

0.1m

d

0.4m

answer is A.

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Detailed Solution

λ=vn=340170=2 m,    n'=340340−17×170 ⇒n'=178.9Hz

Now λ'=vn'=340178.9=1.9 m

⇒λ−λ'=2−1.9=0.1 m

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