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Q.

A spectral line with λ = 4938Ao belongs to the - series of Hydrogen atom

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a

Lyman

b

Balmer

c

Pfund

d

Paschen

answer is B.

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Detailed Solution

\large \bar v = \frac{1}{\lambda } = {R_H}\left( {\frac{1}{{{2^2}}} - \frac{1}{{{4^2}}}} \right)\
\large \bar v = \frac{1}{\lambda } = \frac{{3{R_H}}}{{16}}\
\large \lambda = \frac{{16}}{{3{R_H}}} = 4900A\

 

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