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Q.

A sphere of mass m1 moving with a constant velocity v hits another stationary sphere of the mass m2 elastically.  If after the collision two particles move in opposite direction with equal speed then  m1 :m2 is

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a

1:3

b

3:1

c

2:3

d

2:1

answer is A.

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Detailed Solution

 In case of collision

v2−v1u1−u2=1  ∴ v2+v1=u =2v1(as v1 and v2 has the same magnitude)  Further,  m1u=-m1v1+m2v1  first body reversed m12v1+m1v1=m2v1 m1m2=13 

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