A spherical ball of volume 2000cm3 is subjected to a hydraulic pressure of 15 atm. If the change in volume is 5×10−2cm3, the bulk modulus of the material of the spherical ball is 1atm=105Nm−2

The bulk modulus is given by the formulaB=P∆VV=15×1055×10-22000=6×1010 Nm-2

A spherical ball of volume 2000cm3 is subjected to a hydraulic pressure of 15 atm. If the change in volume is 5×10−2cm3, the bulk modulus of the material of the spherical ball is 1atm=105Nm−2

The bulk modulus is given by the formulaB=P∆VV=15×1055×10-22000=6×1010 Nm-2

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A spherical ball of volume $2000 {cm}^{3}$ is subjected to a hydraulic pressure of 15 atm. If the change in volume is $5 \times 10^{- 2} {cm}^{3}$ , the bulk modulus of the material of the spherical ball is $(1 atm = 10^{5} {Nm}^{- 2})$

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$6 \times 10^{10} {Nm}^{- 2}$

$2 \times 10^{10} {Nm}^{- 2}$

$5 \times 10^{10} {Nm}^{- 2}$

$15 \times 10^{10} {Nm}^{- 2}$

answer is A.

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Detailed Solution

The bulk modulus is given by the formula

$B = \frac{P}{\frac{∆ V}{V}} = \frac{15 \times 10^{5}}{\frac{5 \times 10^{- 2}}{2000}} = 6 \times 10^{10} N m^{- 2}$

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A spherical ball of volume 2000cm3 is subjected to a hydraulic pressure of 15 atm. If the change in volume is 5×10−2cm3, the bulk modulus of the material of the spherical ball is 1atm=105Nm−2

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A spherical ball of volume $2000 {cm}^{3}$ is subjected to a hydraulic pressure of 15 atm. If the change in volume is $5 \times 10^{- 2} {cm}^{3}$ , the bulk modulus of the material of the spherical ball is $(1 atm = 10^{5} {Nm}^{- 2})$