AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

Q.

A spherical body of radius r rolls without slipping on a horizontal surface. Let $L_{C}$ and $L_{p}$ be the magnitudes of angular momenta of the body about the centre of mass and the point of contact, ’p’ respectively. If k is the radius of gyration about an axis passing through the centre of mass, then $[One or more option (s) correct]$

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

a

$L_{P} {= 2L}_{C} if k = r$

b

$L_{P} {= 2L}_{C} i f k < r .$

c

$L_{P} {= 2L}_{C} for all cases$

d

$L_{P} {>2L}_{C} i f k > r .$

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Let the sphere roll without slipping with an angular velocity $ω$ . The velocity of the centre of mass C is given by $υ = w r .$ . The angular momentum of the sphere about the centre C is given by ${\vec{L}}_{C} = {\vec{L}}_{a b o u t, c m} = I_{c m} \vec{w} = - m k^{2} w \hat{k} .$ (1)
Question Image

Question Image

Watch 3-min video & get full concept clarity

courses

No courses found

Related Blogs

Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs

Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

best study material, now at your finger tips!

live classes
progress tracking
24x7 mentored guidance
study plan analysis

download the app

gplay

mentor

Download the App

gplay

personalised 1:1 online tutoring