Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A  spherical  cavity  is  created  in  a  uniform  solid  sphere  of  mass  M  and  radius  R  by removing a part of sphere. The radius of the cavity is r & its centre is at a distance ‘a’ from the centre of the sphere.

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

Gravitational field at the center of the cavity is zero.

b

Gravitation field inside the cavity is uniform.

c

Gravitational field inside the cavity is non-uniform.

d

Gravitational field at the center of the cavity is GMR3.a

answer is B, C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Question Image

Consider superposition of complete sphere of mass M and radius R  and for cavity take negative mass MR3r3 and radius r. g=GMR3a+rGMR3r3r3r=GMR3a Gravitational field is independent of location of point in cavity or we can say the field is uniform inside the cavity.

 

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring