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Q.

A spherical cavity of radius R2  is removed from a solid sphere of radius R as shown in figure. The sphere is placed on a rough horizontal surface as shown. The sphere is given a gentle push. Friction is large enough to prevent slippage. Find the time period of small oscillation

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a

2π177R10g

b

2π745g

c

2π1474g

d

2π1254g

answer is A.

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Detailed Solution

Location of centre of mass of the cavitied sphere is given by
 43π(R3R38)ρx=43πR38ρR2 78x=R16[ρ=density] x=R14
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 Moment of inertia of the cavitied sphere about an axis (r to plane of the figure) through point of contact (P) is calculated as follows
Let M = mass of cavitied sphere
 Mass of sphere of radius R2 is m=ρ43πR38=M7
Mass of sphere without cavity 
 Required moment of inertia
I = (moment of inertia of complete shphere without cavity about an axis through P)
(moment of inertia of the cavity about the same axis)
 758M7R2[4720M7R2]=177140MR2
A purely rolling sphere can be considered to be is pure rotation about the point of contact. Consider the sphere at a slightly displaced position , as shown.

Restoring torque in this position is





 

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