A spherical conductor of radius 10cm has a charge of $3 .2 \times 10^{- 7} C$ distributed uniformly. What is the magnitude of electric field at a point 15 cm from the centre of the sphere
$(\frac{1}{4 π \in_{0}} = 9 \times 10^{9} N m^{2} / C^{2})$

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$1 .28 \times 10^{6} N / C$

$1 .28 \times 10^{7} N / C$

$1 .28 \times 10^{5} N / C$

$1 .28 \times 10^{4} N / C$

answer is A.

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Detailed Solution

$\begin{array}{l} E = \frac{1}{4 {πε}_{0}} . \frac{q}{r^{2}} \\ E = 9 x 10^{9} x \frac{3 .2 x 10^{- 7}}{{(15 x 10^{- 2})}^{2}} \\ E = 1 .28 x 10^{5} N / C \end{array}$

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