A spherical convex surface separates two media having refractive indices $μ_{1} = 1 and μ_{2} = \frac{4}{3}$ . The radius of curvature of the surface is 10 cm. A beam of parallel rays, travelling in vacuum is incident on convex surface. Then the distance of the point in denser medium from the convex surface where the beam will converge is

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$\frac{40}{3} cm$

250 cm

40 cm

30 cm

answer is A.

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Detailed Solution

$\frac{μ_{2}}{v} - \frac{μ_{1}}{u} = \frac{μ_{2} - μ_{1}}{R} \Rightarrow \frac{4 / 3}{v} - \frac{1}{\infty} = \frac{4 / 3 - 1}{(+ 10)}$

$\Rightarrow v = 40 cm$

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