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Q.

A spherical rain drop evaporates at a rate proportional to its surface area at that instant. The radius of the drop initially is 3mm and after one hour it is found to be 2mm if r(t) represents radius of the drop at time ‘t’. then 

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a

r(t)=3+t32t

b

r(t)=3t3

c

r(t)=3+t22t

d

r(t)=3t

answer is A.

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Detailed Solution

We have, dvdt=λ.4πr2  
d(43πr3)dt=λ.4πr2 
4πr2.drdt=λ.4πr2 
  drdt=λr=λt+c1 
We have, r0=3 and r=2 at t=1 
  c=3,  2=λ+3  λ=1r=3t

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