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A spherical shell of radius R is given charge 3q on its surface and a point charge q is placed at distance R/2 from its centre C. Also there is a charge 2q placed outside the shell at a distance of 2R as shown. Then:

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The electric potential at the centre C due to charges on the outer surface of shell is $- \frac{K q}{R}$ after closing the switch S.

Charge flown through the switch into earth after closing the switch S is 4q.

The magnitude of electric field at the centre C due to charges on the surface of shell is $\frac{K q}{R^{2}}$ before closing the switch S.

The electric potential at the centre C due to charges on the outer surface of shell is $- \frac{K q}{R}$ before closing the switch S.

answer is C.

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Detailed Solution

A) E at C due to outside charges=0
E at C due to induced $= \frac{K 2 Q}{{(2 R)}^{2}} = \frac{E Q}{2 R^{2}}$
$(C) \frac{K q^{2}}{2 R} + \frac{K q'}{R} = 0 q' = - q$

D) $Δ Q = 4 q - (- q) = 5 q$

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