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A spherical soap bubble has a radius r. The surface tension of the soap film is T. The energy needed to double the diameter of the bubble at the same temperature is:

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$24 {πr}^{2} T$

$4 {πr}^{2} T$

$2 {πr}^{2} T$

$12 {πr}^{2} T$

answer is A.

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Detailed Solution

$W = 8 πT (R_{2}^{2} - R_{1}^{2}) = 8 πT [{(2 r)}^{2} - r^{2}] = 24 {πr}^{2} T$

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