A spherical surface of radius of curvature 10cm separates two medium X and Y of refractive indices $\frac{4}{3} and \frac{3}{2}$ respectively. If the object is placed along principal axis in medium X, then

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Image is real if the object distance is greater than 90 cm.

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answer is C.

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Detailed Solution

For spherical surface , $\frac{μ_{y}}{V} - \frac{μ_{x}}{U} = \frac{μ_{y} - μ_{x}}{R}$
Here R and U are negative. So to make the Limits of the above equation, V must always be negative.

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