Q.

A spiral loop has inner radius 10 cm and outer radius 20 cm and carries current 1A in each turn. The total number of turn in loop is 100. A small rectangular loop of area 2 cm2 carries current 0.05 A is placed at the centre of loop. If magnitude of potential energy of rectangular loop is  μ0ln2xJ.Calculate  x.

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answer is 200.

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Detailed Solution

 B=μ0NI2(ba)ln(ba)
Potential energy  =M.B=MBcosθ=IABcosθ

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