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A splash is heard 3.12s after a stone is dropped into a well 45 m deep. The speed of sound in air is [g = 10 ms^-2]

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330ms^-1

346ms^-1

340ms^-1

375ms^-1

answer is B.

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Detailed Solution

time of fall $= \sqrt{\frac{2 h}{g}} \Rightarrow t = \sqrt{\frac{2 \times 45}{10}} = 3$

remaining time = 3.12 - 3 = 0.12 sec

speed = 45/0.12 = 375ms^-1

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