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A sports club charges ₹x as a registration fee and there are variable charges for playing any particular sport. Ruchi joined the club to play basketball for a month and paid ₹200. Her friend Sakshi joined the club to play table tennis for a month at ₹150. It is given that the monthly charges for playing basketball is k times the charges of tennis, which is represented by variable y. Which of the following linear equations in terms of x and y represent the given situation?

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x + y = 300, x + ky = 150

x + ky = 200, x + y = 150

x − ky = 200, x − y = 350

x − y = 200, x − ky = 50

answer is B.

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Detailed Solution

Charge of playing tennis = y and charge of playing basketball = ky

Sakshi joined the club to play table tennis for a month at ₹150.

∴ x + y = 150

Ruchi joined the club to play basketball for a month and paid ₹200.

∴ x + ky = 200

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