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Q.

A spring balance is attached to the ceiling of lift. A man hangs his bag on the spring and the spring reads 49 N, when the lift is stationary. If the lift moves downward with an acceleration of 5 m / s2, the reading of the spring balance will be :

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a

24 N 

b

 74N

c

 49 N

d

15 N

answer is B.

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Detailed Solution

Here, R=M(g−a)………..(1)
When lift is stationary R = M g……….(2)
∴ 49=M×9⋅8  or  M=5kg
From eq. (1), R =5 (9.8 -5) =24N

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