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A spring of natural length l is compressed vertically downward against the floor so that its compressed length becomes $\frac{l}{2} .$ When released, the spring attains its natural length. If k is the stiffness constant of spring, then what will be the work done by the spring on the floor?

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zero

$\frac{1}{2} {kl}^{2}$

$\frac{1}{2} k {(\frac{1}{2})}^{2}$

${kl}^{2}$

answer is A.

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Detailed Solution

Displacement of point of application on floor is zero. so work done by spring on floor is zero.

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