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Q.

A spring of spring constant $5 \times 10^{3} N / m$ is stretched initially by 5cm from the unstreched position. Then the work required to stretch it further by another 5cm is

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a

1.5 Nm

b

18.75 Nm

c

25 Nm

d

6.25 m

answer is B.

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Detailed Solution

$W = \frac{1}{2} k (x_{2}^{2} - x_{1}^{2}) = \frac{1}{2} \times \frac{5 \times 10^{3} (10^{2} - 5^{2})}{10^{4}}$
$\begin{array}{l} = \frac{1}{2} \times 5 \times \frac{15 \times 5}{10000} \times 1000 \\ = 0 .25 \times 5 \times 15 \\ = 18 .75 Nm \end{array}$

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