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Q.

A spring when stretched by 2 mm its potential energy becomes 4 J. If it is stretched by 10 mm, its potential energy is equal to                                           

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a

415 J

b

None

c

4 J

d

54 J

answer is D.

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Detailed Solution

U=12kx2  

U α X2   ⇒  U2U1=X22X21

 

  if x becomes 5 times then energy will become 25 times  i.e. 4×25=100J

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