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Q.

A square aluminium (shear modulus is 25 × 109 Nm–2) slab of side 60 cm and thickness 15 cm is subjected to a shearing force (on its narrow face) of 18.0 × 104 N. The lower edge is riveted to the floor. The displacement of the upper edge is ____ μ m.

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answer is 48.

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Detailed Solution

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FA=ηxℓ⇒FℓAη=x⇒x=18×104×60×10−260×10−2×15×10−2×25×109=48×10−6 m=48 μ m

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