A square coil AECD of side 0.1 m is placed in a magnetic field $B=2t^2$. Here, t is in seconds and B is in Tesla. The magnetic field is into the paper. At time $t=2$s, induced electric field in DC is

Magnetic field in $\otimes$ direction passing through the coil is increasing, the therefore, from Len’z law the induced current will be produce magnetic field. Thus, the induced current will be anticlockwise of the induced electric field is along DC.

$\oint \overrightarrow{E}.\overrightarrow{dl}=\left|\frac{d\varphi }{dt}\right|$
Or $E\left(4l\right)=I^2.\left(\frac{dB}{dt}\right)$

Or  $E=\frac{I}{4}\left(4t\right)=\left(I\right)\left(t\right)=\left(0.1\right)\left(2\right)=0.2V/m$