A square coil of side 20 cm consists of 30 turns and carries a current of 10 A, then the magnetic moment of the coil is _______.

 

Choose the correct option.

If a rectangular loop carrying a steady current is placed in a uniform magnetic field then it will experience a torque.

The magnetic moment m for the loo[ is given as, 

m= NIA

 and the torque can be given as,

$𝝉=\mathrm{NIAB}.\mathrm{sin\theta } = \mathrm{mBsin\theta }$

where N= number of turns of the coil, I=current in the loop, A= area enclosed by the loop, B= magnetic field intensity and $\theta$=angle between the normal to the plane of the coil and the direction of a uniform magnetic field.

Given: N=30 turns, x=20 cm=0.2 m, I=10 A

Area enclosed by the square loop is: 

A=0.2²

  =0.04 m²

Magnetic moment, m= NIA

                                       =30 x 10 x 0.04

m=12 Am²