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A square frame, made of copper wire is carrying a current $i = 12 A$ . Length of side of the square is 1 m. If the frame is placed in a magnetic region where $B_{1} = 1 μT and B_{2} = 2 μT,$ then net force experienced by the square frame is

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$18 \times 10^{- 6} N$

$12 \times 10^{- 6} N$

$24 \times 10^{- 6} N$

$36 \times 10^{- 6} N$

answer is B.

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Detailed Solution

$F_{net} = i ℓ B_{1} + i ℓ B_{2} = 12 \times 1 \times (1 + 2) \times 10^{- 6} N = 36 \times 10^{- 6} N$

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