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Q.

A square frame of side 10 cm is lying in an electric field of intensity 20   Vm1. The unit vector normal to the square makes an angle of 60 with the direction of the electric field. The electric flux through the surface enclosed by the frame will be   

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a

Zero

b

0.1   Nm2C1

c

0.2   Nm2C1

d

0.4   Nm2C1

answer is B.

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Detailed Solution

ϕ=EAcosθ=20×10-2×12=0.1

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A square frame of side 10 cm is lying in an electric field of intensity 20   Vm−1. The unit vector normal to the square makes an angle of 60∘ with the direction of the electric field. The electric flux through the surface enclosed by the frame will be