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A square loop of area $2.5 \times 10^{- 3} m^{2}$ and having 100 turns with a total resistance of $100 Ω$ is moved out of a uniform magnetic field of 0.40 T in 1 sec with a constant speed. Then work done, in pulling the loop is

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1 mJ

1 μ J

zero

0.1 mJ

answer is D.

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Detailed Solution

e = \frac{d ϕ}{dt} = \frac{BAN}{t}; w = \frac{e^{2}}{R}, t

$w = \frac{B^{2} A^{2} N^{2}}{{Rt}^{2}} \times t$

$w = \frac{B^{2} A^{2} N^{2}}{Rt}$

$w = \frac{{(0.40)}^{2} \times {(25 \times 10^{- 4})}^{2} \times {(100)}^{2}}{100 \times 1} = 0.1 mJ$

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