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A square metal loop of side 10 cm and resistance $1 Ω$ is moved with a constant velocity partly inside a uniform magnetic field of $2 {Wbm}^{- 2},$ directed into the paper, as shown in the figure. The loop is connected to a network of five resistors each of value $3 Ω .$ If a steady current of 1mA flows in the loop, then the speed of the loop is

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$0 .5 {cms}^{- 1}$

$2 {cms}^{- 1}$

$1 .5 {cms}^{- 1}$

$4 {cms}^{- 1}$

answer is B.

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Detailed Solution

$I = \frac{Bvℓ}{R} \Rightarrow 1 \times 10^{- 3} = \frac{2 \times v \times 10 \times 10^{- 2}}{4} v = 2 {cms}^{- 1}$

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