A square of side ‘a’ has charge Q at its centre and charge ‘q’ at one of the corners. The work required to be done in moving the charge ‘q’ from the corner to the diagonally opposite corner is

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Zero

$\frac{Qq}{4 π \in_{0} a}$

$\frac{Qq \sqrt{2}}{4 π \in_{0} a}$

$\frac{Qq}{2 π \in_{0} a}$

answer is A.

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Detailed Solution

From symmetry of the figure all corner have same electric potential. Therefore work done in moving the charge q from the corner to the diagonally opposite corner is zero.

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