Q.

A square plate of 0.1 m side moves parallel to a second plate with a velocity of 0.1 m/s, both plates being immersed in water. If the viscous force is 0.002 N and the coefficient of viscosity is 0.01 poise, distance between the plates in m is

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a

0.005

b

0.1

c

0.05

d

0.0005

answer is D.

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Detailed Solution

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A=(0.1)2=0.01m2,η=0.01 poise =0.001 decapoise 

 (M.K.S. unit), dv=0.1m/s and F=0.002N

F=ηAdvdx

dx=ηAdvF=0.001×0.01×0.10.002=0.0005m

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