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A square plate of 0.1m side moves parallel to a second plate with a velocity of 0.1m / s , both plates being immersed in water. If the viscous force is 0.002N and the coefficient of viscosity is 0.01 poise, the distance between plates in meters is

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0.1

0.05

0.005

0.0005

answer is D.

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Detailed Solution

Given data, Area: $a^{2} = 0 .1 \times 0 .1 = (0 .1)^{2} m^{2};$
$η = 0 .01 poise = 0 .001 decapoise,$

$d v = 0 .1 m / \sec$
Also, $F = 0 .002 N$

$We know that, F = ηA \frac{dv}{dx}$
$\Rightarrow dx = ηA \frac{dv}{F} = \frac{0 .001 \times (0 .1)^{2} \times 0 .1}{0 .002} = 0 .0005 m$

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