A square plate of 0.1m side moves parallel to a second plate with a velocity of 0.1m / s , both plates being immersed in water. If the viscous force is 0.002N and the coefficient of viscosity is 0.01 poise, the distance between plates in meters is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

0.1

0.05

0.005

0.0005

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Given data, Area: $a^{2} = 0 .1 \times 0 .1 = (0 .1)^{2} m^{2};$
$η = 0 .01 poise = 0 .001 decapoise,$

$d v = 0 .1 m / \sec$
Also, $F = 0 .002 N$

$We know that, F = ηA \frac{dv}{dx}$
$\Rightarrow dx = ηA \frac{dv}{F} = \frac{0 .001 \times (0 .1)^{2} \times 0 .1}{0 .002} = 0 .0005 m$

JEE

NEET

Foundation JEE

Foundation NEET

CBSE