A stair case contains ten steps each 10 cm high and 20 cm wide. The minimum horizontal velocity with which the ball has to be rolled off the upper most step, so as to hit directly the edge of the lowest step is (approximately)

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42ms^-1

4.2ms^-1

24ms^-1

2.4ms^-1

answer is B.

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Detailed Solution

$R = u \sqrt{\frac{2 h}{g}}$ here R=nb and h=nh' where b is the width of each stair and h' is the height of each steps.

$nb = u \sqrt{\frac{2 nh'}{g}}$

$u = \sqrt{\frac{gn}{2 h'}} b = \sqrt{\frac{9.8 \times 10}{2 \times 0.1}} 0.2 = 4.2 m / s$

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