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A staircase contains three steps each $10 c m$ high and $20 c m$ wide. What should be the minimum horizontal velocity of the ball rolling off the uppermost plane so as to hit directly the lowest plane? $(i n m s^{- 1})$

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Detailed Solution

If $u$ is the minimum speed , $x = 40, y = 20, θ = 0^{0}$

$y = \tan θ - g \frac{x^{2} \sec^{2} θ}{2 u^{2}}$

$Where g = 10 {ms}^{- 2} = 1000 {cms}^{- 2}$

$- 20 = \frac{800000}{2 u^{2}}; u = 200 c m s^{- 1} = 2 m s^{- 1}$

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