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A star emitting light of wavelength $5896 Å$ is moving away from the earth with a speed of 3600 km/s. The wavelength of light observed on earth will

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$decrease by 5825.25 Å$

$increase by 5966.75 Å$

$decrease by 70.75 Å$

$increase by 70.75 Å$

answer is D.

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Detailed Solution

$Δλ = \frac{v}{c} λ = \frac{3600 \times 10^{3}}{3 \times 10^{8}} \times 5896 = 70 .75 Å$

So the increased wavelength of light is observed.

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