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A stationary mass of gas is compressed without friction from an initial state of $0.3 m^{3}$ and 0.105 M Pa to final state of $0.15 m^{3}$ and 0.105 M Pa. The pressure remaining constant. During the process there is a transfer of 37.6 kJ of heat from the system. During the process the amount of internal energy change is

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-28.85 KJ

-21.85 KJ

-21.85 J

-53.35 KJ

answer is B.

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Detailed Solution

$∆ W = - 105 \times (0.15 - 0.3) kJ = + 15.75 kJ ∆ q = - 37.6 kJ ∴ ∆ E = ∆ W + ∆ q = - 37.6 + 15.75 = - 21.85 kJ$

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