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A stationary shell explodes into two fragments, having masses in the ratio of 1:2. The heavier fragment attains a Kinetic energy of 100 J. The Kinetic energy released in the explosion is

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600 J

150 J

200 J

300 J

answer is C.

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Detailed Solution

$K\,\,\alpha \frac{1}{m}\left( {K = \frac{{{p^2}}}{{2m}}} \right) \Rightarrow \frac{{{k_1}}}{{{k_2}}} = \frac{{{m_2}}}{{{m_1}}}$
$\frac{{100}}{{{k_2}}} = \frac{1}{2} \Rightarrow {{\rm{k}}_{\rm{2}}}{\rm{ = 200J}}$

$\therefore$ k = k₁ + k₂ ⇒ 100 + 200 = 300J

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