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Q.

A stationary shell explodes into two fragments, having masses in the ratio of 1:2. The heavier fragment attains a Kinetic energy of 100J. The Kinetic energy released in the explosion is

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a

200 J

b

150 J

c

300 J

d

600 J

answer is C.

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Detailed Solution

$\begin{array}{l} KE \propto \frac{1}{m} (K = \frac{p^{2}}{2 m}) \Rightarrow \frac{k_{1}}{k_{2}} = \frac{m_{2}}{m_{1}} (p = momentum is same for both in magnitude) \\ \frac{100}{k_{2}} = \frac{1}{2} \Rightarrow k_{2} = 200 J \\ ∴ k = k_{1} + k_{2} \Rightarrow 100 + 200 = 300 J \end{array}$

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