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Q.

A stationary source is emitting sound at a fixed frequency  f0, which is reflected by two cars approaching the source. The difference between the frequencies of sound reflected from the car is 1.2%  of  f0. What is the difference in the speed of the cars in meters per second to the nearest integer? The cars are moving at constant speeds much smaller than the speed of sound which is  330ms1.

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answer is 2.

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Detailed Solution

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fapp=f0c+vcv,  where c is speed of sound
       df=2f0c(cv)2dv2f0c(cv)2dv=2f0cdv                            …(i) 
     Given  df=1.2100f0
           From Eqs. (i) and (ii)  dv2m/s=7km/h.

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