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A stationary wave set up on a string have the equation y = (2 mm) sin $[(6.28 m^{- 1}) x \cos (ω t)]$ . This stationary wave is created by two identical waves, of amplitude A each moving in opposite directions along the string. Then,

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A = 2 mm

A = 4 mm

the smallest length of the string is 50 cm

the smallest length of the string is 2m

answer is C.

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Detailed Solution

$\begin{array}{l} \frac{2 π}{λ} = 6.28 \\ ∴ λ = 1 m \\ \frac{λ}{2} = l_{s m a l l e s t} \end{array}$

0.5 m = l = 50 cm

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