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A steady current of $1 Ampere$ flows through a conductor in $1 second$ then the number of electrons that passes through the conductor is [[1]] ${\times 10}^{18}$ .

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Detailed Solution

If a steady current of

1 A

flows through a conductor for

1 s

, then the number of electrons that passes through the conductor is

6.25 {\times 10}^{18}

.
It is given that the current flowing in the circuit

I = 1 A

for time

t = 1 s

.
It is known that the charge is equal to

q = It = ne

\Rightarrow It = ne

\Rightarrow n = \frac{It}{e}

\Rightarrow n = \frac{1 \times 1}{{1.6 \times 10}^{- 19}}

\Rightarrow n = 6.25 \times 10^{18} electrons

Hence, the number of electrons that passes through the conductor is

6.25 \times 10^{18}

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