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A steam at 100°C is passed into 1kg of water contained in a calorimeter of water equivalent 0.2kg at 9^oC, till the temperature of the calorimeter and water in it is increased to 90°C.The mass of steam condensed in kg is nearly (sp. Heat of water =1 cal/g.°C, Latent heat of vaporization = 540 cal/g)

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0.18

0.54

0.27

0.81

answer is B.

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Detailed Solution

m × 540 + m(1)(10) = 1200(1)(81)

$m = \frac{{1200 \times 81}}{{550}} = 176.7gm \cong 0.18kg$

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